Find the effective resistance of the series . combination of three resistors of resistances 10 Omega , 20 Omega and 30 Omega .

Find the effective resistance of the combination of two resistors of resistances 10 Omega and 15 Omega connected in series (ii) parallel.

Choose the correct alternative and write it along its allotted alphabet: The effective resistance of a parallel combination of two resistors is 60 Omega and 40 Omega is ………..

How will you connect three resistors of resistances 3 Omega each to obtain a resistance of 4.5 Omega ?

Find the resistance of 60 W, 240 V bulb.

If two resistors connected in parallel, the effective resistance of the combination is 21 Omega . If the same two resistors are connected in series, the effective resistance of the combination is 100 Omega . Find the resistances of the individual resistors.

When two resistors are connected in series, their effective resistance is 80 Omega . When : they are connected in parallel, their effective resistance is 20 Omega . What are the values of the two resistances?

Consider a series combination of two resistors of resistances 10 Omega and 40 Omega across which a potential difference of 5 V is applied. Find the current in the circuit and the potential difference across each resistor.

Choose the correct alternative and write it along its allotted alphabet: When three resistors, each of resistance R, are connected in parallel the effective resistance is 10 Omega . Hence, R must be…… A. 5 Omega B. 10 Omega C. 20 Omega D. 30 Omega

Choose correct alternative. The emf of a cell of negligible internal resistance is 2 V. It is connected to the series combination of 2 Omega , 3 Omega and 5 Omega resistances. The potential difference across 3 Omega resistance will be (in volt)