lf `sin A= 3/5 ` and `cos B=9/41`, `0 < A <pi/2` , `-pi/2 ltBlt0` then `sin (A-B)` is equal to:

If sin A=3/5 and cos B=9/41, 0ltAltpi/2 , 0ltBltpi/2 ,find the value of cos (A-B).

If sin A = (3)/(5) and cos B = (9)/(41) , 0 lt A lt (pi)/(2), 0 lt B lt (pi)/(2) Find the value of sin (A + B)

If sin A=3/5 and cos B = 9/41, 0 lt A lt pi/2 and 0 lt B lt pi/2 . Find the values of that : sin (A+B)

If sin A = (3)/(5) and cos B = (9)/(41) , 0 lt A lt (pi)/(2), 0 lt B lt (pi)/(2) Find the value of cos (A - B)

If sinA=3/5 and cosB=9/41, 0 < A < pi/2 and 0 < B < pi/2 then find the values of (i) sin(A+B) (ii) sin(A-B) (iii) cos(A+B) (iv) cos(A-B)

If sinA=3/5 and cosB=9/41, 0 < A < pi/2 and 0 < B < pi/2 then find the values of (i) sin(A+B) (ii) sin(A-B) (iii) cos(A+B) (iv) cos(A-B)

If tanA=3/4 , cosB=9/(41) , where pi lt A lt (3pi)/2 and 0 lt B lt pi/2 , find tan(A+B)

If sin(A + B) = 1 and 2 sin (A - B) = 1, where 0 lt A, B lt pi/2 then what is tan A:tan B equal to?