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Electric Potential of Sphere

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Two conducting spheres of radius R and 3R carry charges Q and -2 Q . Between these spheres a neutral conducting sphere of radius 2R is connected. The separation between the sphere is considerably large Charge flows through conducting wire due to potential difference. The final electric potential of sphere of radius 3R will be :

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In the previous question, if V is the electric potential of the first sphere, what would be the electric potential of the second sphere ?

If the electric potential of the inner metal sphere is 10 volt & that of the outer shell is 5 volt then the potential at the centre will be

A non-uniformly charged ring is kept near an uncharged conducting solid sphere. The distance between their centres (which are on the same line normal to the plane of the ring) is 1 and their radius is R. If total charge on the ring is Q then the electric potential of the sphere will be:

7S is a solid neutral conducting sphere. A point charge q of 1 × 10–6 C is placed at point A. C is the centre of sphere and AB is a tangent. BC = 3m and AB = 4m. (1) The electric potential of the conductor is 1.8 kV (2) The electric potential of the conductor is 2.25 kV (3) The electric potential at B due to induced charges on the sphere is – 0.45 kV (4) The electric potential at B due to induced charges on the sphere is 0.45 kV

STATEMENT-1: For practical purposes, the earth is used as a reference at zero potencial in electrical circuits. and STATEMENT-2: The electrical potential of a sphere of radius R with charge Q uniformly distributed on the surface is given by (Q)/(4piepsilon_0R) .

Two isolated charged conducting spheres of radii a and b produce the same electric field near their surface. The ratio of electric potentials on their surfaces is

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In the above problem, find the electric field and electric potential at the centre of the sphere due to induced charges on the sphere?