Benzene has vapour pressure of 70 torr and methyl benzene has 20 torr. If we have an equimolar mixture of both then find mole fraction of benzene in vapour phase?

At 20^@ C, the vapour pressure of benzene is 70 torr and that of methyl benzene is 20 torr. The mole fraction of benzene in the vapour phase at 20^@ C above an equimolar mixture of benzene and methyl benzene is ________ xx 10^(-2) . (Nearest integer)

At 88^(@)C benzene has a vapour pressure of 900 torr and toluene has a vapour pressure of 360 torr. What is the mole fraction of benzene in the mixture with toluene that will boil at 88^(@)C at 1 atm pressure? (Consider that benzene toluene form an ideal solution):

Benzene and toluene forms an ideal solution. Vapour pressure of pure benzene is 100 torr while that of pure toluene is 50 torr. If mole faction of benzene in liquid phase is (1)/(3) . Then calculate the mole fraction of benzene in vapour phase :