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If A=[(1,0),(0,1)] B=sum(r=1)^2021A^r th...

If `A=[(1,0),(0,1)]` `B=sum_(r=1)^2021A^r` then value of `abs(B)` is

A

2021

B

`(2021)^2`

C

-2021

D

0

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The correct Answer is:
A
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