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If z^(2)+(p+iq)z+(r+is)=0, where,p,q,r,s...

If `z^(2)+(p+iq)z+(r+is)=0`, where,p,q,r,s are non-zero has real roots, then

A

`pqr = r^(2) + p^(2) s`

B

` prs = q^(2) + r^(2) p`

C

` qrs = p^(2) + s^(2) q`

D

` pqs = s^(2) + q^(2) r`

Text Solution

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The correct Answer is:
D
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