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The value of `x` satisfying the equation `|x-1|^(log_(3)x^(2)-2log_(x)9)=(x-1)^(7)` is

A

`3`

B

`9`

C

`27`

D

`81

Text Solution

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The correct Answer is:
To solve the equation \( |x-1|^{(\log_3 x^2 - 2 \log_x 9)} = (x-1)^7 \), we can follow these steps: ### Step 1: Analyze the Absolute Value Since we have an absolute value, we need to consider two cases based on the value of \( x \). **Case 1:** \( x - 1 \geq 0 \) (i.e., \( x \geq 1 \)) In this case, we can drop the absolute value: \[ (x-1)^{(\log_3 x^2 - 2 \log_x 9)} = (x-1)^7 \] **Case 2:** \( x - 1 < 0 \) (i.e., \( x < 1 \)) Here, we have: \[ -(x-1)^{(\log_3 x^2 - 2 \log_x 9)} = (x-1)^7 \] However, since \( (x-1)^7 \) is negative for \( x < 1 \), this case is not valid. ### Step 2: Simplify the Equation From Case 1, we can equate the exponents since the bases are the same: \[ \log_3 x^2 - 2 \log_x 9 = 7 \] ### Step 3: Rewrite the Logarithms Using the properties of logarithms, we can rewrite \( \log_x 9 \): \[ \log_x 9 = \frac{\log_3 9}{\log_3 x} = \frac{2}{\log_3 x} \] Thus, substituting this back into the equation gives us: \[ \log_3 x^2 - 2 \left(\frac{2}{\log_3 x}\right) = 7 \] ### Step 4: Substitute \( t = \log_3 x \) Let \( t = \log_3 x \). Then, we have: \[ 2t - \frac{4}{t} = 7 \] ### Step 5: Clear the Fraction Multiply through by \( t \) (assuming \( t \neq 0 \)): \[ 2t^2 - 4 = 7t \] Rearranging gives: \[ 2t^2 - 7t - 4 = 0 \] ### Step 6: Solve the Quadratic Equation Using the quadratic formula \( t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \): \[ t = \frac{7 \pm \sqrt{(-7)^2 - 4 \cdot 2 \cdot (-4)}}{2 \cdot 2} \] \[ t = \frac{7 \pm \sqrt{49 + 32}}{4} \] \[ t = \frac{7 \pm \sqrt{81}}{4} \] \[ t = \frac{7 \pm 9}{4} \] Calculating the two possible values for \( t \): 1. \( t = \frac{16}{4} = 4 \) 2. \( t = \frac{-2}{4} = -\frac{1}{2} \) ### Step 7: Convert Back to \( x \) Now, we convert back to \( x \): 1. For \( t = 4 \): \[ \log_3 x = 4 \implies x = 3^4 = 81 \] 2. For \( t = -\frac{1}{2} \): \[ \log_3 x = -\frac{1}{2} \implies x = 3^{-\frac{1}{2}} = \frac{1}{\sqrt{3}} \approx 0.577 \] ### Step 8: Determine Valid Solutions Since we are considering \( x \geq 1 \), we discard \( x = \frac{1}{\sqrt{3}} \). Thus, the only valid solution is: \[ \boxed{81} \]
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  6. The number of solutions the equation |x+1|^(log(x+1)(3+2x-x^(2)))=(x-3...

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  8. log(10)x+log(10)x^(1//2)+log(10)x^(1//4)+....=y and (1+3+5+...(2y-1))/...

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  10. The number of solutions of the equation log(x-3)(x^(3)-3x^(2)-4x+8)=3 ...

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  11. Let [x] denote the greatest integer function. The number of solutions ...

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  13. If xlog(10)(10//3)+log(10)3=log(10)(2+3^(x))+x, then x=

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  14. If log(y)x+log(x)y=2,x^(2)+y=12, then the values of x,y are

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  17. If log(2)xy=5,log(1//2)(x//y)=1, then the values of x,y are

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  18. If (log)(10)[1/(2^x+x-1)]=x[(log)(10)5-1] , then x= 4 (b) 3 (c) 2 ...

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  19. For agt0, ne 1 the roots of the equation log(ax)a+log(x)a^(2)+log(a^(2...

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