`(a) to 3 (b) to 1 (c ) to 4 (d) to 2` (a) `(x-3)^(2) gt 0` for all real values of x except `x=3` (b) `(x+1)(x-4) lt 0 =>x` lies between `-1` and `4` (c ) `Delta=-`ive and hence its sign is same as of the first term `AA` real values of x (d) `-3x^(2)+4x-5 gt 0 =>3x^(2)-4x+5 le 0` Assuming as in (c ) , `Delta=-` ive and hence its sign is same as of 3 i.e. Hence there will be no real values of x for which this will hold.
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