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If the number of terms in the expansion ...

If the number of terms in the expansion of `(x-2y +3z)^(n)` is 45, then n =

A

7

B

8

C

9

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding \( n \) such that the number of terms in the expansion of \( (x - 2y + 3z)^n \) is 45, we can follow these steps: ### Step 1: Understand the Formula for the Number of Terms The number of terms in the expansion of \( (a + b + c)^n \) is given by the formula: \[ \text{Number of terms} = \binom{n + r - 1}{r - 1} \] where \( r \) is the number of different variables in the expression. In our case, \( r = 3 \) (for \( x \), \( -2y \), and \( 3z \)). ### Step 2: Substitute the Values into the Formula Substituting \( r = 3 \) into the formula gives: \[ \text{Number of terms} = \binom{n + 3 - 1}{3 - 1} = \binom{n + 2}{2} \] We know that this equals 45, so we set up the equation: \[ \binom{n + 2}{2} = 45 \] ### Step 3: Expand the Binomial Coefficient The binomial coefficient \( \binom{n + 2}{2} \) can be expressed as: \[ \binom{n + 2}{2} = \frac{(n + 2)(n + 1)}{2} \] Setting this equal to 45 gives: \[ \frac{(n + 2)(n + 1)}{2} = 45 \] ### Step 4: Eliminate the Fraction To eliminate the fraction, multiply both sides by 2: \[ (n + 2)(n + 1) = 90 \] ### Step 5: Expand and Rearrange the Equation Expanding the left side: \[ n^2 + 3n + 2 = 90 \] Rearranging gives: \[ n^2 + 3n + 2 - 90 = 0 \] which simplifies to: \[ n^2 + 3n - 88 = 0 \] ### Step 6: Solve the Quadratic Equation Now we can solve the quadratic equation using the quadratic formula: \[ n = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] where \( a = 1 \), \( b = 3 \), and \( c = -88 \): \[ n = \frac{-3 \pm \sqrt{3^2 - 4 \cdot 1 \cdot (-88)}}{2 \cdot 1} \] Calculating the discriminant: \[ n = \frac{-3 \pm \sqrt{9 + 352}}{2} \] \[ n = \frac{-3 \pm \sqrt{361}}{2} \] \[ n = \frac{-3 \pm 19}{2} \] ### Step 7: Calculate the Possible Values of \( n \) Calculating the two possible values: 1. \( n = \frac{16}{2} = 8 \) 2. \( n = \frac{-22}{2} = -11 \) (not valid since \( n \) must be non-negative) Thus, the only valid solution is: \[ n = 8 \] ### Final Answer The value of \( n \) is \( 8 \). ---
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ML KHANNA-BINOMIAL THEOREM AND MATHEMATICAL INDUCTION -Self Assessment Test
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  12. If C(0), C(1), C(2),.....,C(n) are binomial coefficients, (where C(r) ...

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