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What will be the co ordinates of the poi...

What will be the co ordinates of the point `(4,2sqrt(3))` when the axes are rotated through an angle of `30^(@)` in clockwise sense?

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To find the coordinates of the point \( (4, 2\sqrt{3}) \) when the axes are rotated through an angle of \( 30^\circ \) in the clockwise direction, we can use the formulas for rotation of coordinates. ### Step-by-Step Solution: 1. **Identify the Original Coordinates:** The original coordinates of the point are given as: \[ (x, y) = (4, 2\sqrt{3}) \] 2. **Determine the Angle of Rotation:** Since the rotation is clockwise, we need to use \( -30^\circ \) (negative because clockwise is considered negative in standard mathematics). 3. **Use the Rotation Formulas:** The formulas for the new coordinates \( (x', y') \) after rotation are: \[ x' = x \cos(\theta) + y \sin(\theta) \] \[ y' = -x \sin(\theta) + y \cos(\theta) \] where \( \theta = -30^\circ \). 4. **Calculate \( \cos(-30^\circ) \) and \( \sin(-30^\circ) \):** Using trigonometric values: \[ \cos(-30^\circ) = \cos(30^\circ) = \frac{\sqrt{3}}{2} \] \[ \sin(-30^\circ) = -\sin(30^\circ) = -\frac{1}{2} \] 5. **Substitute the Values into the Formulas:** Now substitute \( x = 4 \), \( y = 2\sqrt{3} \), \( \cos(-30^\circ) \), and \( \sin(-30^\circ) \) into the rotation formulas: \[ x' = 4 \cdot \frac{\sqrt{3}}{2} + 2\sqrt{3} \cdot \left(-\frac{1}{2}\right) \] \[ y' = -4 \cdot \left(-\frac{1}{2}\right) + 2\sqrt{3} \cdot \frac{\sqrt{3}}{2} \] 6. **Simplify the Expressions:** For \( x' \): \[ x' = 2\sqrt{3} - \sqrt{3} = \sqrt{3} \] For \( y' \): \[ y' = 2 + 3 = 5 \] 7. **Final Coordinates:** Therefore, the coordinates of the point after the rotation are: \[ (x', y') = (\sqrt{3}, 5) \] ### Final Answer: The coordinates of the point \( (4, 2\sqrt{3}) \) when the axes are rotated through an angle of \( 30^\circ \) in the clockwise sense are \( (\sqrt{3}, 5) \).
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