If the given lines be `3x+4y-11=0` and `12x-5y-2=0`, then find the bisectors of the angles between them and discriminate which bisects the acute angle or which bisects the obtuse angle .

Find the equations of the bisectors of the angles between the planes 2x-y+2z+3=0 and 3x-2y+6z+8=0 and specify the plane which bisects the acute angle and the plane which bisects the obtuse angle.

For the straight lines 4x+3y-6=0 and 5x+12y+9=0, find the equation of the bisector of the obtuse angle between them, bisector of the acute angle between them,and bisector of the angle which contains (1,2)

Show that the origin lies in the acute angles between the planes x + 2y + 2z – 9 = 0 and 4x – 3y + 12z + 13 = 0. Find the planes bisecting the angles between them and point out the one which bisects the acute angle.

Find the equation of the bisector planes of the angles between the planes 2x-y+2z-19=0 and 4x-3y+12z+3=0 and specify the plane which bisects the acute angle and the planes which bisects the obtuse angle.

Find the bisector of acute angle between the lines x+y - 3 = 0 and 7x - y + 5 = 0

The equations of the bisectors of the angles between the straight line 3x-4y+7=0 and 12x-5y-8=0 , are:

For the straight line 4x + 3y - 6 = 0 and 5x + 12y + 9 = 0 , find the equation of the bisector of the obtuse angle between them.

The equation of the bisector of the angle between the lines x-7y+5=0,5x+5y=3 which is the supplement of the angle containing the origin will be