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Equation of the straight lines through the point (3,-2) and inclined at `60^(@)` to the line `sqrt(3)x+y=1` are ……….

Text Solution

Verified by Experts

The correct Answer is:
`y+2=0,xsqrt(3)-y-2+3sqrt(3)`
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Explore conceptually related problems

Show that the equations of the straight lines passing through the point (3,-2) and inclined at 60^(@) to the line sqrt(3)x+y=1 arey +2=0 and y-sqrt(3)x+2+3sqrt(3)=0

straight line passing through origin and inclined at 60^(@) the line sqrt(3)x+y=1 is

Knowledge Check

  • The equation of the straight line passing through the point (3,2) and perpendicular to the line y=x is

    A
    `x-y=5`
    B
    `x+y=5`
    C
    `x+y=1`
    D
    `x-y=1`
  • Equation of straight line passing through the points (2,0) and (0, -3) is

    A
    `(x)/(2) - (y)/(3) =1`
    B
    `(y)/(3) - (x)/(2) =1`
    C
    `(x)/(3) - (y)/(2) = 1`
    D
    `(y)/(2) - (x)/(3) =1 `
  • Similar Questions

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    A straight line L through the point (3,-2) is inclined at an angle 60^(@) the line sqrt(3)x+y=1 If L also intersects the x -axis then the equation of L is

    Find the equations t the straight lines passing through the point (2,3) and inclined at an angle of 45^0 to the line \ 3x+y-5=0.

    Find the equation of the straight line that passes through the point (3,4) and is perpendicular to the line 3x+2y+5=0

    Find the equation of the straight line which passes through the origin and makes angle 60^(@) with the line x+sqrt(3)y+sqrt(3)=0

    (i) Find the equations of the straight line passing through the point (2,3,-1) and is perpendicular to the lines : ( x-2)/(2) = (y + 1)/(1) = (z - 3)/(-3) and (x - 3)/(1) = (y + 2)/(1) = (z - 1)/(1) . (ii) Find the equation of the line which intersects the lines : (x + 2)/(1) = (y - 3)/(2) = (z + 1)/(4) and (x - 1)/(2) = (y - 2)/(3) = (z - 3)/(4) Perpendicular and passes through the point (1,1,1) .

    Find the equation of a straight line passing through the point (4,5) and equally inclined to the lines 3x=4y+7 and 5y=12x+6