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The triangle joinilng the points A(2,7),...

The triangle joinilng the points A(2,7),B(4,-1),C(-2,6) is

A

equilateral

B

Right angled

C

isosceles

D

None of these

Text Solution

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The correct Answer is:
To determine the type of triangle formed by the points A(2,7), B(4,-1), and C(-2,6), we will calculate the lengths of the sides using the distance formula and then check if it satisfies the Pythagorean theorem to identify if it is a right triangle. ### Step 1: Calculate the length of side AB Using the distance formula: \[ AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] For points A(2,7) and B(4,-1): \[ AB = \sqrt{(4 - 2)^2 + (-1 - 7)^2} = \sqrt{(2)^2 + (-8)^2} = \sqrt{4 + 64} = \sqrt{68} \] ### Step 2: Calculate the length of side BC For points B(4,-1) and C(-2,6): \[ BC = \sqrt{(-2 - 4)^2 + (6 - (-1))^2} = \sqrt{(-6)^2 + (7)^2} = \sqrt{36 + 49} = \sqrt{85} \] ### Step 3: Calculate the length of side AC For points A(2,7) and C(-2,6): \[ AC = \sqrt{(-2 - 2)^2 + (6 - 7)^2} = \sqrt{(-4)^2 + (-1)^2} = \sqrt{16 + 1} = \sqrt{17} \] ### Step 4: Check if the triangle is a right triangle To determine if the triangle is a right triangle, we will check if the square of the longest side is equal to the sum of the squares of the other two sides. We have: - \(AB^2 = 68\) - \(BC^2 = 85\) - \(AC^2 = 17\) Now, we check: \[ AB^2 + AC^2 = 68 + 17 = 85 = BC^2 \] Since \(AB^2 + AC^2 = BC^2\), we conclude that triangle ABC is a right triangle. ### Final Conclusion The triangle joining the points A(2,7), B(4,-1), and C(-2,6) is a right triangle. ---
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Knowledge Check

  • The triangle joining the points P(2,7), Q(4,-1), R(-2,6) is

    A
    scalene triangle
    B
    Isosceles triangle
    C
    right angled triangle
    D
    equilateral traingle
  • The triangle formed by the points A(2a,4a),B(2a,6a) and C(2a+sqrt(3a),5a) is

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    right angled
    B
    isosceles
    C
    equilateral
    D
    None of these
  • The triangle formed by the points A(2a,4a),B(2a,6a) and C(2a+sqrt(3)a,5a) is

    A
    right angled
    B
    isosceles
    C
    equilateral
    D
    None
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