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Let O (0,0),P(3,4),Q(6,0) be the vertice...

Let O (0,0),P(3,4),Q(6,0) be the vertices of the triangle OPQ. The point R inside the triangle OPQ is such that the triangles OPR,PQR,OQR are of equal area. The coordinates of R are

A

`(3,2/3)`

B

`(4/3,3)`

C

`(3,4/3)`

D

`(4/3,2/3)`

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The correct Answer is:
To find the coordinates of point R inside triangle OPQ such that the areas of triangles OPR, PQR, and OQR are equal, we can use the property of the centroid of a triangle. The centroid divides the triangle into three smaller triangles of equal area. ### Step-by-Step Solution: 1. **Identify the vertices of the triangle OPQ:** - O(0, 0) - P(3, 4) - Q(6, 0) 2. **Calculate the coordinates of the centroid (R):** The formula for the centroid (G) of a triangle with vertices (x1, y1), (x2, y2), and (x3, y3) is given by: \[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) \] 3. **Substituting the coordinates of points O, P, and Q into the centroid formula:** - \(x_1 = 0\), \(y_1 = 0\) - \(x_2 = 3\), \(y_2 = 4\) - \(x_3 = 6\), \(y_3 = 0\) Now, calculate the x-coordinate of the centroid: \[ x_G = \frac{0 + 3 + 6}{3} = \frac{9}{3} = 3 \] Next, calculate the y-coordinate of the centroid: \[ y_G = \frac{0 + 4 + 0}{3} = \frac{4}{3} \] 4. **Thus, the coordinates of point R (the centroid) are:** \[ R\left(3, \frac{4}{3}\right) \] ### Final Answer: The coordinates of point R are \(R\left(3, \frac{4}{3}\right)\). ---
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ML KHANNA-RECTANGULAR CARTESIAN CO-ORDINATE SYSTEM AND THE STRAIGHT LINE-SELF ASSESSMENT TEST
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