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The lines 2x+3y-4z=0 ,3x-4y+z=7 5x-y-3z...

The lines
`2x+3y-4z=0 ,3x-4y+z=7`
`5x-y-3z+12=0, x-7y+5z-6=0``
` are parellel.

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To prove that the given lines are parallel, we need to analyze the direction ratios of the lines represented by the equations. The equations of the lines are: 1. \( 2x + 3y - 4z = 0 \) 2. \( 3x - 4y + z = 7 \) 3. \( 5x - y - 3z + 12 = 0 \) 4. \( x - 7y + 5z - 6 = 0 \) ### Step 1: Convert the equations into vector form For the first two lines: 1. From \( 2x + 3y - 4z = 0 \), we can express it in vector form as: \[ \vec{r_1} = \lambda (2\hat{i} + 3\hat{j} - 4\hat{k}) \] where \( \lambda \) is a parameter. 2. From \( 3x - 4y + z = 7 \), we can express it in vector form as: \[ \vec{r_2} = \mu (3\hat{i} - 4\hat{j} + \hat{k}) + \vec{a} \] where \( \vec{a} \) is a point on the line. ### Step 2: Find the direction ratios of the lines The direction ratios for the first line \( 2x + 3y - 4z = 0 \) are \( (2, 3, -4) \). The direction ratios for the second line \( 3x - 4y + z = 7 \) are \( (3, -4, 1) \). ### Step 3: Check if the direction ratios are proportional To check if the lines are parallel, we need to see if the direction ratios are proportional. This means we need to find a constant \( k \) such that: \[ \frac{2}{3} = \frac{3}{-4} = \frac{-4}{1} \] Calculating these ratios: 1. \( \frac{2}{3} \) is not equal to \( \frac{3}{-4} \). 2. \( \frac{3}{-4} \) is not equal to \( \frac{-4}{1} \). Since the ratios are not equal, the first two lines are not parallel. ### Step 4: Repeat for the next two lines Now, we will analyze the last two lines: 1. From \( 5x - y - 3z + 12 = 0 \), the direction ratios are \( (5, -1, -3) \). 2. From \( x - 7y + 5z - 6 = 0 \), the direction ratios are \( (1, -7, 5) \). ### Step 5: Check if these direction ratios are proportional To check if the lines are parallel, we need to find a constant \( k \) such that: \[ \frac{5}{1} = \frac{-1}{-7} = \frac{-3}{5} \] Calculating these ratios: 1. \( \frac{5}{1} = 5 \) 2. \( \frac{-1}{-7} \approx 0.14 \) 3. \( \frac{-3}{5} = -0.6 \) Since the ratios are not equal, the last two lines are also not parallel. ### Conclusion Since neither pair of lines is parallel, we conclude that the given lines are not parallel.
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ML KHANNA-CO-ORDINATE GEOMETRY OF THREE DIMENSION-MISCELLANEOUS EXERCISE(TRUE AND FALSE)
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  9. The lines (x-1)/1=(y-2)/2=(z-3)/3 and x/2=(y+2)/2=(z-3)/-2 are paral...

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  10. The lines (x-1)/2=(y-2)/2=(z-3)/0 and (x-2)/0=(y+3)/0=(z-4)/1 are pa...

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  11. The plane x-2y+z-6=0 and the line x/1=y/2=z/3 are related as the line ...

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  12. Find the length of the perpendicular from point (3,4,5) on the line (x...

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  13. Find the angle between the lines in which the planes : 3x - 7y - 5z ...

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  14. The lines 2x+3y-4z=0 ,3x-4y+z=7 5x-y-3z+12=0, x-7y+5z-6=0 are parell...

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  15. The lines (x-5)/4=(y-7)/4=(z+3)/-5 and (x-8)/7=(y-4)/1=(z-5)/3 are cop...

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  16. A sphere of constant radius k , passes through the origin and me...

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  17. A variable plane passes through a fixed point (a ,b ,c) and cuts th...

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  18. If any tangent plane to the sphere x^(2) + y^(2) +z^(2) makes interc...

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