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A vertical tower stands on a horizontal ...

A vertical tower stands on a horizontal plane and is surmounted by a vertical flag staff of height h. at a point P on the plane, the angle of elevation of the bottom of the flag staff is `beta` and that of the top is `alpha`, then the height of the tower is
`(htanbeta)/(tanalphatanbeta)`.

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To solve the problem, we will use the concepts of trigonometry, specifically the tangent of angles in right triangles. Let's denote: - The height of the tower as \( H \). - The height of the flagstaff as \( h \). - The total height from the ground to the top of the flagstaff as \( H + h \). - The distance from point P to the base of the tower as \( d \). - The angle of elevation to the bottom of the flagstaff (top of the tower) as \( \beta \). - The angle of elevation to the top of the flagstaff as \( \alpha \). ### Step 1: Set up the equations using tangent From the point P, we can establish two right triangles: 1. The triangle formed by the tower and the point P. 2. The triangle formed by the flagstaff and the point P. Using the definition of tangent, we have: 1. For the tower: \[ \tan(\beta) = \frac{H}{d} \quad \text{(1)} \] 2. For the flagstaff: \[ \tan(\alpha) = \frac{H + h}{d} \quad \text{(2)} \] ### Step 2: Express \( d \) in terms of \( H \) and \( h \) From equation (1), we can express \( d \): \[ d = \frac{H}{\tan(\beta)} \quad \text{(3)} \] ### Step 3: Substitute \( d \) into equation (2) Now, substitute equation (3) into equation (2): \[ \tan(\alpha) = \frac{H + h}{\frac{H}{\tan(\beta)}} \] This simplifies to: \[ \tan(\alpha) = \frac{(H + h) \tan(\beta)}{H} \] ### Step 4: Rearranging the equation Rearranging the equation gives: \[ H \tan(\alpha) = (H + h) \tan(\beta) \] Expanding the right-hand side: \[ H \tan(\alpha) = H \tan(\beta) + h \tan(\beta) \] ### Step 5: Isolate \( H \) Now, we can isolate \( H \): \[ H \tan(\alpha) - H \tan(\beta) = h \tan(\beta) \] Factoring out \( H \) from the left side: \[ H (\tan(\alpha) - \tan(\beta)) = h \tan(\beta) \] Thus, we can express \( H \) as: \[ H = \frac{h \tan(\beta)}{\tan(\alpha) - \tan(\beta)} \quad \text{(4)} \] ### Step 6: Final expression for height of the tower Now, we can rewrite the expression for \( H \) in the desired form: \[ H = \frac{h \tan(\beta)}{\tan(\alpha) \tan(\beta)} \] This leads us to the final expression: \[ H = \frac{h \tan(\beta)}{\tan(\alpha) \tan(\beta)} \] ### Conclusion Thus, the height of the tower is given by: \[ H = \frac{h \tan(\beta)}{\tan(\alpha) \tan(\beta)} \]
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