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The curve (x/a)^n+(y/b)^n =2 touches th...

The curve `(x/a)^n+(y/b)^n` =2 touches the straight line `x/a+y/b=2` at the point (a,b) then the value of n is

A

2

B

3

C

4

D

any real number

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The correct Answer is:
To solve the problem, we need to determine the value of \( n \) such that the curve \( \left(\frac{x}{a}\right)^n + \left(\frac{y}{b}\right)^n = 2 \) touches the line \( \frac{x}{a} + \frac{y}{b} = 2 \) at the point \( (a, b) \). ### Step 1: Find the derivative of the curve We start with the equation of the curve: \[ \left(\frac{x}{a}\right)^n + \left(\frac{y}{b}\right)^n = 2 \] Differentiating both sides with respect to \( x \): \[ \frac{d}{dx}\left(\left(\frac{x}{a}\right)^n\right) + \frac{d}{dx}\left(\left(\frac{y}{b}\right)^n\right) = 0 \] Using the chain rule, we get: \[ n \left(\frac{x}{a}\right)^{n-1} \cdot \frac{1}{a} + n \left(\frac{y}{b}\right)^{n-1} \cdot \frac{1}{b} \cdot \frac{dy}{dx} = 0 \] ### Step 2: Rearranging the derivative Rearranging the equation gives: \[ n \left(\frac{y}{b}\right)^{n-1} \cdot \frac{1}{b} \cdot \frac{dy}{dx} = -n \left(\frac{x}{a}\right)^{n-1} \cdot \frac{1}{a} \] Dividing both sides by \( n \) (assuming \( n \neq 0 \)): \[ \left(\frac{y}{b}\right)^{n-1} \cdot \frac{1}{b} \cdot \frac{dy}{dx} = -\left(\frac{x}{a}\right)^{n-1} \cdot \frac{1}{a} \] Thus, we have: \[ \frac{dy}{dx} = -\frac{b}{a} \cdot \frac{\left(\frac{x}{a}\right)^{n-1}}{\left(\frac{y}{b}\right)^{n-1}} \] ### Step 3: Evaluate the slope at the point (a, b) Substituting \( x = a \) and \( y = b \): \[ \frac{dy}{dx}\bigg|_{(a,b)} = -\frac{b}{a} \cdot \frac{\left(\frac{a}{a}\right)^{n-1}}{\left(\frac{b}{b}\right)^{n-1}} = -\frac{b}{a} \] ### Step 4: Find the slope of the line The line \( \frac{x}{a} + \frac{y}{b} = 2 \) can be rewritten as: \[ y = -\frac{b}{a}x + 2b \] The slope of this line is also \( -\frac{b}{a} \). ### Step 5: Conclusion about the value of n Since the slopes of the curve and the line are equal at the point \( (a, b) \), and since the slope does not depend on \( n \), we conclude that the value of \( n \) can be any real number. Thus, the final answer is: \[ \text{The value of } n \text{ is any real number.} \]
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