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If the tangent at P on the curve x^my^n ...

If the tangent at P on the curve `x^my^n =d^(m+n)` meets the co-ordinates axes at A and B, then AP : PB=

A

`m:n`

B

`n:m`

C

`-m:n`

D

`-n:m`

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The correct Answer is:
To solve the problem of finding the ratio \( AP : PB \) where the tangent at point \( P \) on the curve \( x^m y^n = d^{m+n} \) meets the coordinate axes at points \( A \) and \( B \), we can follow these steps: ### Step 1: Understand the Curve The given curve is \( x^m y^n = d^{m+n} \). We can rewrite this in logarithmic form to make differentiation easier. ### Step 2: Take Logarithm Taking the logarithm of both sides, we have: \[ \log(x^m y^n) = \log(d^{m+n}) \] Using the property of logarithms, this simplifies to: \[ m \log x + n \log y = (m+n) \log d \] ### Step 3: Differentiate Implicitly Let \( P \) be the point \( (x_1, y_1) \) on the curve. We differentiate both sides with respect to \( x \): \[ \frac{d}{dx}(m \log x + n \log y) = 0 \] This gives us: \[ \frac{m}{x} + n \frac{1}{y} \frac{dy}{dx} = 0 \] Rearranging this, we find: \[ \frac{dy}{dx} = -\frac{m y}{n x} \] ### Step 4: Find the Slope at Point \( P \) At point \( P(x_1, y_1) \), the slope \( m \) of the tangent line is: \[ m = -\frac{m y_1}{n x_1} \] ### Step 5: Write the Equation of the Tangent Line The equation of the tangent line at point \( P \) can be written as: \[ y - y_1 = m (x - x_1) \] Substituting for \( m \): \[ y - y_1 = -\frac{m y_1}{n x_1} (x - x_1) \] ### Step 6: Find Points \( A \) and \( B \) To find the x-intercept (point \( A \)), set \( y = 0 \): \[ 0 - y_1 = -\frac{m y_1}{n x_1} (x - x_1) \] Solving for \( x \): \[ x = x_1 + \frac{n x_1}{m} \] Thus, the coordinates of point \( A \) are: \[ A \left( x_1 + \frac{n x_1}{m}, 0 \right) \] To find the y-intercept (point \( B \)), set \( x = 0 \): \[ y - y_1 = -\frac{m y_1}{n x_1} (0 - x_1) \] Solving for \( y \): \[ y = y_1 + \frac{m y_1}{n} \] Thus, the coordinates of point \( B \) are: \[ B \left( 0, y_1 + \frac{m y_1}{n} \right) \] ### Step 7: Calculate Distances \( AP \) and \( PB \) The distance \( AP \) can be calculated as: \[ AP = \left| x_1 + \frac{n x_1}{m} - x_1 \right| = \frac{n x_1}{m} \] The distance \( PB \) can be calculated as: \[ PB = \left| y_1 + \frac{m y_1}{n} - y_1 \right| = \frac{m y_1}{n} \] ### Step 8: Find the Ratio \( AP : PB \) Now, we can find the ratio: \[ AP : PB = \frac{\frac{n x_1}{m}}{\frac{m y_1}{n}} = \frac{n^2 x_1}{m^2 y_1} \] However, since we are looking for the ratio of the segments \( AP \) and \( PB \) directly, we can simplify to: \[ AP : PB = n : m \] ### Final Answer Thus, the ratio \( AP : PB \) is: \[ \boxed{n : m} \]
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ML KHANNA-TANGENTS AND NORMALS-PROBLEM SET (2) (MULTIPLE CHOICE QUESTIONS)
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  9. The length of the normal to the curve x= a(t +sin t),y = a(1-cos t), "...

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  11. The portion of the tangent of the curve x^(2/3)+y^(2/3)=a^(2/3) ,which...

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  12. At a point (a// 8, a// 8) on the curve x^(1//3) + y^(1//3) = a^(1//3) ...

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  13. In the curve x =a [cost+ log tan (t // 2)], y =a sin t, the portion of...

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  14. The triangle formed by the tangent to the curve f(x)=x^2+bx-b the poin...

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  16. The length of the normal to the curve at (x, y) y=a((e^(x//a)+e^(-x//a...

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  17. The value of n for which the length of the subnormal of the curve xy^n...

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  18. If the tangent at P on the curve x^my^n =d^(m+n) meets the co-ordinate...

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  19. For the parabola y^2 = 4ax, the ratio of the subtangentto the abscissa...

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  20. The tangent at any point. on the curve x^4+y^4=a^4 cuts off intercepts...

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