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In the curve x^(m+n)=a^(m-n)y^(2n), mth ...

In the curve `x^(m+n)=a^(m-n)y^(2n)`, mth power of subtangent varies as the nth power of the sub-normal.

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To prove that the mth power of the subtangent varies as the nth power of the sub-normal for the curve given by the equation \( x^{m+n} = a^{m-n} y^{2n} \), we will follow these steps: ### Step 1: Differentiate the given equation We start with the equation of the curve: \[ x^{m+n} = a^{m-n} y^{2n} \] Differentiating both sides with respect to \( x \): \[ \frac{d}{dx}(x^{m+n}) = \frac{d}{dx}(a^{m-n} y^{2n}) \] Using the product rule on the right side: \[ (m+n)x^{m+n-1} = a^{m-n} \cdot 2n y^{2n-1} \frac{dy}{dx} \] ### Step 2: Solve for \(\frac{dy}{dx}\) Rearranging the equation to solve for \(\frac{dy}{dx}\): \[ \frac{dy}{dx} = \frac{(m+n)x^{m+n-1}}{2n a^{m-n} y^{2n-1}} \] ### Step 3: Define subtangent and sub-normal The subtangent \( T \) and sub-normal \( N \) are defined as follows: - Subtangent: \[ T = \left| \frac{y}{\frac{dy}{dx}} \right| \] - Sub-normal: \[ N = y \cdot \frac{dy}{dx} \] ### Step 4: Calculate \( T \) and \( N \) Substituting \(\frac{dy}{dx}\) into the formula for \( T \): \[ T = \left| \frac{y}{\frac{(m+n)x^{m+n-1}}{2n a^{m-n} y^{2n-1}}} \right| = \frac{2n a^{m-n} y^2}{(m+n)x^{m+n-1}} \] For \( N \): \[ N = y \cdot \frac{(m+n)x^{m+n-1}}{2n a^{m-n} y^{2n-1}} = \frac{(m+n)x^{m+n-1} y}{2n a^{m-n} y^{2n-1}} = \frac{(m+n)x^{m+n-1}}{2n a^{m-n} y^{2n-2}} \] ### Step 5: Establish the relationship between \( T^m \) and \( N^n \) Now we need to find \( T^m \) and \( N^n \): \[ T^m = \left( \frac{2n a^{m-n} y^2}{(m+n)x^{m+n-1}} \right)^m \] \[ N^n = \left( \frac{(m+n)x^{m+n-1}}{2n a^{m-n} y^{2n-2}} \right)^n \] ### Step 6: Show that \( T^m \) is proportional to \( N^n \) From the expressions of \( T^m \) and \( N^n \), we can see that: \[ T^m \propto N^n \] This means that the mth power of the subtangent is directly proportional to the nth power of the sub-normal. ### Conclusion Thus, we have proven that the mth power of the subtangent varies as the nth power of the sub-normal for the given curve. ---
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