If m be the order and n the degree of the differential equation `((d^(2)y)/(dx^(2)))^(2)+x((dy)/(dx))^(2)=0` then (m, n) =
A
(2, 2)
B
(3, 3)
C
(2, 3)
D
none
Text Solution
AI Generated Solution
The correct Answer is:
To find the order \( m \) and degree \( n \) of the given differential equation
\[
\left(\frac{d^2y}{dx^2}\right)^2 + x\left(\frac{dy}{dx}\right)^2 = 0,
\]
we will follow these steps:
### Step 1: Identify the Order of the Differential Equation
The order of a differential equation is defined as the highest derivative present in the equation.
In the given equation, we have:
- The term \( \frac{d^2y}{dx^2} \) which is the second derivative of \( y \).
- The term \( \frac{dy}{dx} \) which is the first derivative of \( y \).
The highest derivative present is \( \frac{d^2y}{dx^2} \), which is the second derivative. Therefore, the order \( m \) of the differential equation is:
\[
m = 2.
\]
### Step 2: Identify the Degree of the Differential Equation
The degree of a differential equation is defined as the power of the highest order derivative when the equation is a polynomial in derivatives.
In our equation, we can rewrite it as:
\[
\left(\frac{d^2y}{dx^2}\right)^2 + x\left(\frac{dy}{dx}\right)^2 = 0.
\]
Here, the highest order derivative \( \frac{d^2y}{dx^2} \) is raised to the power of 2. Thus, the degree \( n \) of the differential equation is:
\[
n = 2.
\]
### Step 3: Conclusion
Now that we have determined both the order and the degree, we can express the final answer as:
\[
(m, n) = (2, 2).
\]
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