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If m be the order and n the degree of th...

If m be the order and n the degree of the differential equation `((d^(2)y)/(dx^(2)))^(2)+x((dy)/(dx))^(2)=0` then (m, n) =

A

(2, 2)

B

(3, 3)

C

(2, 3)

D

none

Text Solution

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The correct Answer is:
To find the order \( m \) and degree \( n \) of the given differential equation \[ \left(\frac{d^2y}{dx^2}\right)^2 + x\left(\frac{dy}{dx}\right)^2 = 0, \] we will follow these steps: ### Step 1: Identify the Order of the Differential Equation The order of a differential equation is defined as the highest derivative present in the equation. In the given equation, we have: - The term \( \frac{d^2y}{dx^2} \) which is the second derivative of \( y \). - The term \( \frac{dy}{dx} \) which is the first derivative of \( y \). The highest derivative present is \( \frac{d^2y}{dx^2} \), which is the second derivative. Therefore, the order \( m \) of the differential equation is: \[ m = 2. \] ### Step 2: Identify the Degree of the Differential Equation The degree of a differential equation is defined as the power of the highest order derivative when the equation is a polynomial in derivatives. In our equation, we can rewrite it as: \[ \left(\frac{d^2y}{dx^2}\right)^2 + x\left(\frac{dy}{dx}\right)^2 = 0. \] Here, the highest order derivative \( \frac{d^2y}{dx^2} \) is raised to the power of 2. Thus, the degree \( n \) of the differential equation is: \[ n = 2. \] ### Step 3: Conclusion Now that we have determined both the order and the degree, we can express the final answer as: \[ (m, n) = (2, 2). \]
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