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The happening of any one of the two mutu...

The happening of any one of the two mutually exclusive events A and B is

A

`P[A].P[B]`

B

`P(A)+P(B)-P(A capB)`

C

`P[A]+P[B]`

D

none

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem regarding the probability of the happening of either event A or event B, which are mutually exclusive events, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Mutually Exclusive Events**: - Mutually exclusive events are events that cannot occur at the same time. This means that if one event occurs, the other cannot. 2. **Identifying the Required Probability**: - We need to find the probability of either event A or event B occurring. This is represented as P(A ∪ B), which denotes the probability of the union of events A and B. 3. **Using the Formula for Probability of Union**: - The general formula for the probability of the union of two events A and B is: \[ P(A ∪ B) = P(A) + P(B) - P(A ∩ B) \] - Here, P(A ∩ B) represents the probability that both events A and B occur simultaneously. 4. **Applying the Condition of Mutual Exclusivity**: - Since events A and B are mutually exclusive, the probability of both events occurring together, P(A ∩ B), is 0. This simplifies our formula: \[ P(A ∪ B) = P(A) + P(B) - 0 \] - Therefore, we can simplify it to: \[ P(A ∪ B) = P(A) + P(B) \] 5. **Conclusion**: - The probability of either event A or event B occurring is simply the sum of their individual probabilities: \[ P(A ∪ B) = P(A) + P(B) \] ### Final Answer: Thus, the probability of the happening of any one of the two mutually exclusive events A and B is: \[ P(A ∪ B) = P(A) + P(B) \]
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