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If P(A)=0*65,P(B)=0*15,P(overline(A))+P(...

If `P(A)=0*65,P(B)=0*15,P(overline(A))+P(overline(B))=`

A

`1*5`

B

`1*2`

C

`0*8`

D

none

Text Solution

AI Generated Solution

The correct Answer is:
To find \( P(\overline{A}) + P(\overline{B}) \), we can follow these steps: ### Step 1: Calculate \( P(\overline{A}) \) The probability of the complement of event \( A \) is given by: \[ P(\overline{A}) = 1 - P(A) \] Given \( P(A) = 0.65 \): \[ P(\overline{A}) = 1 - 0.65 = 0.35 \] ### Step 2: Calculate \( P(\overline{B}) \) Similarly, the probability of the complement of event \( B \) is given by: \[ P(\overline{B}) = 1 - P(B) \] Given \( P(B) = 0.15 \): \[ P(\overline{B}) = 1 - 0.15 = 0.85 \] ### Step 3: Add \( P(\overline{A}) \) and \( P(\overline{B}) \) Now we can add the probabilities of the complements: \[ P(\overline{A}) + P(\overline{B}) = 0.35 + 0.85 \] Calculating this gives: \[ P(\overline{A}) + P(\overline{B}) = 1.20 \] ### Final Answer Thus, the final answer is: \[ P(\overline{A}) + P(\overline{B}) = 1.20 \] ---
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