P(A cup B)=P(A cap B)` if and only if the relation between P(A) and P(B) is …………

If P((A)/(C))>P((B)/(C)) and P((A)/(bar(C)))>P((B)/(bar(C))), then the relationship between P(A) and P(B) is (A)P(A)=P(B) (B) P(A) P(B)(D)P(A)>=P(B)

If 'P(A cup B)'='P(A cap B)' for any two events A and B ,then

Assertion (A) : Let A and B be two events such that the occurrence of A implies occurrence of B, but not vice - versa, then the correct relation between P(A) and P (B) is P(B) ge P(A) Reason (R) : Here, according to the given statement A sube B P (B) = P (A cup (A cap B)) " " ( :' A cap B = A ) = P (A) + P (A cap B) Therefore, P (B) ge P (A)

If A and B are two complementary events, then what is the relation between P(A) and P(B).

P(A uu B)=P(A nn B) if and only (i) P(A)>P(B)( ii )P(A)

If A and B are two given events, then P(A cap B) is

If P(A cup B) = P(A) + P(B) , then what can be said about the events A and B ?

Let A and B be two events such that P(A cup B)=P(A cap B) . Then, Statement-1: P(A cap overline(B))=P(overline(A) cap B)=0 Statement-2: P(A)+P(B)=1

For two given events A and B, P(A cup B) is