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If ((1-3p))/2,((1+4p))/3,((1+p))/6 are t...

If `((1-3p))/2,((1+4p))/3,((1+p))/6` are the probabilities of three mutually excusing and exhaustive events, then the set of all values of `p` is a. (0,1) b. (-1/4,1/3) c. (0,1/3) d.

A

(0,1)

B

`(-(1)/(4),(1)/(3))`

C

`(0,(1)/(3))`

D

`(0,oo)`

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A, C, D
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