Home
Class 12
MATHS
Fifteen coupons are numbered 1,2, . . .,...

Fifteen coupons are numbered 1,2, . . .,15 respectively. Seven coupons are selected at random one at a time with replacement. The probability that the largest number appearing on a selected coupon is 9, is

A

`((9)/(10))^(6)`

B

`((8)/(15))^(7)`

C

`((3)/(5))^(7)`

D

none

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the probability that the largest number appearing on a selected coupon is 9 when we select 7 coupons from a set of 15 numbered coupons (1 to 15) with replacement. ### Step-by-Step Solution: 1. **Understanding the Problem**: We are selecting 7 coupons, and we want the largest number among those selected coupons to be 9. This means that all selected numbers must be from the set {1, 2, 3, 4, 5, 6, 7, 8, 9}. 2. **Identifying Favorable Outcomes**: The favorable outcomes are the numbers from 1 to 9. Therefore, when we select a coupon, it can only be one of these 9 numbers. 3. **Calculating Total Outcomes**: Since there are 15 coupons, the total number of outcomes for selecting one coupon is 15. When selecting 7 coupons, the total number of possible outcomes is: \[ 15^7 \] 4. **Calculating Favorable Outcomes**: The number of favorable outcomes (where the selected numbers are from 1 to 9) for each selection is 9. Therefore, the total number of favorable outcomes when selecting 7 coupons is: \[ 9^7 \] 5. **Finding the Probability**: The probability \( P \) that the largest number appearing on a selected coupon is 9 can be calculated using the formula: \[ P = \frac{\text{Number of favorable outcomes}}{\text{Total outcomes}} = \frac{9^7}{15^7} \] This simplifies to: \[ P = \left(\frac{9}{15}\right)^7 = \left(\frac{3}{5}\right)^7 \] 6. **Final Result**: Thus, the probability that the largest number appearing on a selected coupon is 9 is: \[ P = \left(\frac{3}{5}\right)^7 \]
Promotional Banner

Topper's Solved these Questions

  • PROBABILITY

    ML KHANNA|Exercise MISCELLANEOUS EXERCISE (Comprehension)|1 Videos
  • PROBABILITY

    ML KHANNA|Exercise MISCELLANEOUS EXERCISE (Assertion / Reason)|1 Videos
  • PROBABILITY

    ML KHANNA|Exercise Problem Set (1) FILL IN THE BLANKS|17 Videos
  • PERMUTATIONS AND COMBINATIONS

    ML KHANNA|Exercise SELF ASSESSMENT TEST|20 Videos
  • PROGRESSIONS

    ML KHANNA|Exercise MISCELLANEOUS EXERCISE (ASSERTION/REASON) |1 Videos

Similar Questions

Explore conceptually related problems

Fifteen coupens are numbered 1,2,3,...15 respectively.Seven coupons are selected at random one at a time with replacement The Probability that the largest number appearing on a selected coupon is 9 is :

Fifteen coupons are numbered 1, 2, 3,…, 15 respectively. Seven coupons are selected random one at a time with replacement. The probability that the largest number appearing on the selected coupons is atmost 9, is :

Seven chits are numbered 1 to 7. Four chits are drawn one by one with replacment.The probability that the least number appearing on any selected chit is 5 is :

Three numbers are selected at random one by one with replacement from the numbers 1,2,3,….60. The probability that the A.M. of the numbers selected is 15 is.

Twenty coupons are numbered 1,2,3......,20 respectively.Four coupons are selected at random without replacement.If maximum and minimum numbers on selected coupons are 12 and 3 respectively.Then the probability that the maximum number on the remaining selected coupons is 9 is (1)(5)/(56) (2) (5)/(28) (3) (15)/(28) (4) (8)/(56)

From the set of numbers {1,2,3,4,5,6,7,8} two numbers are selected at random without replacement.The probability that their sum is more than 13 is

ML KHANNA-PROBABILITY-Self Assessment Test
  1. A purse contains 4 copper coins, 3 silver coins, the second purse cont...

    Text Solution

    |

  2. Two persons, A and B, have respectively n+1 and n coins, which they to...

    Text Solution

    |

  3. Fifteen coupons are numbered 1,2, . . .,15 respectively. Seven coupons...

    Text Solution

    |

  4. An unbiased die with faced marked 1, 2, 3, 4, 5, and 6 is rolled four ...

    Text Solution

    |

  5. A box contains 100 tickets, numbered 1,2,3, . . .100. two tickets are ...

    Text Solution

    |

  6. A student appears for tests I, II and III. The student is successful i...

    Text Solution

    |

  7. If (1+3p)/(3),(1-p)/(4) and (1-2p)/(2) are the probabilities of three ...

    Text Solution

    |

  8. If (1-3p)/(2),(1+4p)/(3) and (1+p)/(6) are the probabilities of three ...

    Text Solution

    |

  9. Urn A contains 6 red and 4 black balls and urn B contains 4 red and 6 ...

    Text Solution

    |

  10. One hundred identical coins, each with probability p , of showing up h...

    Text Solution

    |

  11. India plays two matches each with West Indies and Australia. In any ma...

    Text Solution

    |

  12. There are 3 bags each containing 5 white balls and 2 black balls, and ...

    Text Solution

    |

  13. Consider a family with two children. Assume that each child is as like...

    Text Solution

    |

  14. A coin is tossed 3 times. The probability of obtaining at least two he...

    Text Solution

    |

  15. 8 coins are tossed simultaneously. The probability of getting at least...

    Text Solution

    |

  16. A sample of size 4 is drawn with replacement (without replacement) fro...

    Text Solution

    |

  17. If two events A and B are such that P(A^(C))=0*3 P(B)=0*4 and P(AB^(...

    Text Solution

    |

  18. If A and B are two events such that P(A cupB)=5//6,P(AcapB)=1//3,P(ove...

    Text Solution

    |

  19. A and B each throw a die. Then it is 7:5 that A's throw is not greater...

    Text Solution

    |

  20. Two persons each makes a single throw with a die. The probability they...

    Text Solution

    |