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Let E^(@) denotes the complement of an ...

Let `E^(@)` denotes the complement of an event E. If E, F, G are pairwise independent events with `P(G) gt 0` and `P (E nn F nn G) =0`. Then, `P(E^(@) nn F^(@)|G)` equals :

A

`P(E^(C))+P(F^(C))`

B

`P(E^(C))-P(F^(C))`

C

`P(E^(C))-P(F)`

D

`P(E)-P(F^(C))`

Text Solution

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The correct Answer is:
C
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Knowledge Check

  • Let E^(C) denote the complement of an event E. Let E_(1),E_(2) and E_(3) be any pairwise independent events with P(E_(1))gt0 and P(E_(1)nn E_(2) nn E_(3))=0 . Then P(E_(2)^(C)nnE_(3)^(C)//E_(1)) is equal to :

    A
    `P(E_(3)^(C))-P(E_(2)^(C))`
    B
    `P(E_(3))-P(E_(2)^(C))`
    C
    `P(E_(3)^(C))-P(E_(2))`
    D
    `P(E_(2)^(C))+P(E_(3))`
  • If P (E) denotes the probability of an event E, then:

    A
    `0 lt P (E ) le 1`
    B
    `0 lt P (E ) lt 1`
    C
    `0 le P (E ) le 1`
    D
    `0 le P (E ) lt 1`
  • If E and F are events with P(E) le P(F) and P(E nn F) gt 0, then

    A
    occurrence of E `rArr` occurrence of F
    B
    occurrence of F `rArr` occurrence of E
    C
    non-occurrence of E `rArr` non-occurrence of F
    D
    none of the above implication hold
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