A distribution has mean `=8*7`, median `=8*5` and mode `=7*3`. The distribution is

Options

A. positively skewed
B. negatively skewed
C. symmetrical
D. none of these

Answer

To determine the nature of the distribution based on the given mean, median, and mode, we can follow these steps:

### Step 1: Identify the given values
- Mean = \(8 \times 7 = 56\)
- Median = \(8 \times 5 = 40\)
- Mode = \(7 \times 3 = 21\)

### Step 2: Compare the values of mean, median, and mode
We have:
- Mean = 56
- Median = 40
- Mode = 21

### Step 3: Analyze the relationship between mean, median, and mode
To classify the distribution, we need to check the following conditions:
- If Mean > Median > Mode, the distribution is positively skewed.
- If Mean < Median < Mode, the distribution is negatively skewed.
- If Mean = Median = Mode, the distribution is symmetrical.

In our case:
- Mean (56) > Median (40) > Mode (21)

### Step 4: Conclusion
Since the mean is greater than the median, and the median is greater than the mode, we conclude that the distribution is positively skewed.

### Final Answer
The distribution is positively skewed.

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