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The numbers 3,5,7,4 have frequencies x,x...

The numbers 3,5,7,4 have frequencies `x,x+4,x-3,x+8`. If their arithmetic mean is 4, the value of x is

A

`5/3`

B

`7/4`

C

`2/3`

D

none of these

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The correct Answer is:
To solve the problem, we need to find the value of \( x \) given that the numbers 3, 5, 7, and 4 have frequencies \( x, x+4, x-3, x+8 \) respectively, and their arithmetic mean is 4. ### Step-by-Step Solution: 1. **Identify the numbers and their frequencies**: - Numbers: 3, 5, 7, 4 - Frequencies: \( x, x+4, x-3, x+8 \) 2. **Calculate the total frequency**: \[ \text{Total frequency} = x + (x + 4) + (x - 3) + (x + 8) = 4x + 9 \] 3. **Calculate the weighted sum of the numbers**: \[ \text{Weighted sum} = 3x + 5(x + 4) + 7(x - 3) + 4(x + 8) \] Expanding this: \[ = 3x + 5x + 20 + 7x - 21 + 4x + 32 \] Combining like terms: \[ = (3x + 5x + 7x + 4x) + (20 - 21 + 32) = 19x + 31 \] 4. **Set up the equation for the arithmetic mean**: The arithmetic mean is given by: \[ \text{Mean} = \frac{\text{Weighted sum}}{\text{Total frequency}} = 4 \] Therefore, we have: \[ \frac{19x + 31}{4x + 9} = 4 \] 5. **Cross-multiply to eliminate the fraction**: \[ 19x + 31 = 4(4x + 9) \] Expanding the right side: \[ 19x + 31 = 16x + 36 \] 6. **Rearranging the equation**: \[ 19x - 16x = 36 - 31 \] Simplifying: \[ 3x = 5 \] 7. **Solve for \( x \)**: \[ x = \frac{5}{3} \] ### Final Answer: The value of \( x \) is \( \frac{5}{3} \).
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