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p ^^ ~| p is :...

`p ^^ ~| p` is :

A

False

B

True

C

p

D

q

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \( p \land \neg p \) (which reads as "p and not p"), we can follow these steps: ### Step 1: Understand the symbols The expression \( p \land \neg p \) consists of: - \( p \): a proposition that can either be true (T) or false (F). - \( \neg p \): the negation of \( p \), which is true when \( p \) is false and false when \( p \) is true. - \( \land \): the logical conjunction (AND) operator, which is true only when both operands are true. **Hint for Step 1:** Identify the components of the expression and their meanings. ### Step 2: Analyze the conjunction The conjunction \( p \land \neg p \) can be evaluated based on the truth values of \( p \): - If \( p \) is true (T), then \( \neg p \) is false (F). Therefore, \( p \land \neg p = T \land F = F \). - If \( p \) is false (F), then \( \neg p \) is true (T). Therefore, \( p \land \neg p = F \land T = F \). **Hint for Step 2:** Evaluate the expression for both possible truth values of \( p \). ### Step 3: Conclusion In both cases, whether \( p \) is true or false, the expression \( p \land \neg p \) evaluates to false (F). Hence, the overall value of \( p \land \neg p \) is false. **Hint for Step 3:** Summarize the results of your evaluation to reach a conclusion. ### Final Answer The expression \( p \land \neg p \) is always false.
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