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(p vv q) ^^ q = is ..........

`(p vv q) ^^ q =` is .......

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To solve the expression `(p ∨ q) ∧ q`, we will create a truth table to evaluate the expression step by step. ### Step 1: Identify the Variables We have two variables: - \( P \) - \( Q \) ### Step 2: Create the Truth Table Structure We will create a truth table with the following columns: 1. \( P \) 2. \( Q \) 3. \( P ∨ Q \) (Disjunction) 4. \( (P ∨ Q) ∧ Q \) (Conjunction) ### Step 3: Fill in the Truth Values The possible truth values for \( P \) and \( Q \) are: - True (T) - False (F) Thus, we will have the following combinations for \( P \) and \( Q \): 1. \( P = T, Q = T \) 2. \( P = T, Q = F \) 3. \( P = F, Q = T \) 4. \( P = F, Q = F \) ### Step 4: Calculate \( P ∨ Q \) Now we will calculate the values for \( P ∨ Q \): - When \( P = T \) and \( Q = T \), \( P ∨ Q = T \) - When \( P = T \) and \( Q = F \), \( P ∨ Q = T \) - When \( P = F \) and \( Q = T \), \( P ∨ Q = T \) - When \( P = F \) and \( Q = F \), \( P ∨ Q = F \) ### Step 5: Calculate \( (P ∨ Q) ∧ Q \) Now we will calculate the values for \( (P ∨ Q) ∧ Q \): - When \( P = T \) and \( Q = T \), \( (P ∨ Q) ∧ Q = T ∧ T = T \) - When \( P = T \) and \( Q = F \), \( (P ∨ Q) ∧ Q = T ∧ F = F \) - When \( P = F \) and \( Q = T \), \( (P ∨ Q) ∧ Q = T ∧ T = T \) - When \( P = F \) and \( Q = F \), \( (P ∨ Q) ∧ Q = F ∧ F = F \) ### Step 6: Summarize the Truth Table Now we can summarize our truth table: | P | Q | P ∨ Q | (P ∨ Q) ∧ Q | |-------|-------|-------|-------------| | T | T | T | T | | T | F | T | F | | F | T | T | T | | F | F | F | F | ### Step 7: Analyze the Results Now we can compare the column for \( (P ∨ Q) ∧ Q \) with the column for \( Q \): - The values of \( (P ∨ Q) ∧ Q \) are: T, F, T, F - The values of \( Q \) are: T, F, T, F Since the columns for \( (P ∨ Q) ∧ Q \) and \( Q \) are identical, we conclude that: \[ (P ∨ Q) ∧ Q \equiv Q \] ### Final Answer Thus, the expression `(p ∨ q) ∧ q` is equivalent to \( Q \). ---
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