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A man, in a lift ascending with the acce...

A man, in a lift ascending with the acceleration `fm//"sec"^(2)`, throws a ball vertically upwards with a velocity v and catches it after time `t_(1)` . Afterwards when the lift is descending with the same acceleration the man again throws a ball vertically upwards with the same velocity and catches it after time `t_(2)` . The velocity v and acceleration f in terms.of `t_(1),t_(2)` where g is the acceleration due to gravity.

Text Solution

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The correct Answer is:
`f= (t_(2)-t_(1))/(t_(2)+t_(1)), v= (t_(1)t_(2))/(t_(1)+t_(2))g`
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