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A sphere impinges directly on an equal s...

A sphere impinges directly on an equal sphere at rest. If the coefficient of restitution is 1/2, then their velocities after the impact are in the ratio

A

`1:2`

B

`2:3`

C

`1:3`

D

`3:4`

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The correct Answer is:
To solve the problem of two equal spheres colliding, we will use the principles of conservation of momentum and the coefficient of restitution. ### Step 1: Define the Variables Let: - \( m \) = mass of each sphere (since they are equal) - \( u_1 \) = initial velocity of the first sphere (before impact) - \( u_2 \) = initial velocity of the second sphere (at rest, so \( u_2 = 0 \)) - \( v_1 \) = final velocity of the first sphere (after impact) - \( v_2 \) = final velocity of the second sphere (after impact) - \( e \) = coefficient of restitution = \( \frac{1}{2} \) ### Step 2: Apply Conservation of Momentum According to the law of conservation of momentum: \[ m u_1 + m u_2 = m v_1 + m v_2 \] Since \( u_2 = 0 \), the equation simplifies to: \[ m u_1 = m v_1 + m v_2 \] Dividing through by \( m \): \[ u_1 = v_1 + v_2 \quad (1) \] ### Step 3: Apply the Coefficient of Restitution The coefficient of restitution is defined as: \[ e = \frac{v_2 - v_1}{u_1 - u_2} \] Substituting \( u_2 = 0 \): \[ e = \frac{v_2 - v_1}{u_1} \] Substituting \( e = \frac{1}{2} \): \[ \frac{1}{2} = \frac{v_2 - v_1}{u_1} \] Rearranging gives us: \[ v_2 - v_1 = \frac{1}{2} u_1 \quad (2) \] ### Step 4: Solve the Equations Now we have two equations: 1. \( u_1 = v_1 + v_2 \) 2. \( v_2 - v_1 = \frac{1}{2} u_1 \) From equation (2), we can express \( v_2 \) in terms of \( v_1 \): \[ v_2 = v_1 + \frac{1}{2} u_1 \quad (3) \] Substituting equation (3) into equation (1): \[ u_1 = v_1 + \left(v_1 + \frac{1}{2} u_1\right) \] This simplifies to: \[ u_1 = 2v_1 + \frac{1}{2} u_1 \] Rearranging gives: \[ u_1 - \frac{1}{2} u_1 = 2v_1 \] \[ \frac{1}{2} u_1 = 2v_1 \] Thus: \[ u_1 = 4v_1 \quad (4) \] ### Step 5: Find the Ratio of Velocities Now substituting \( u_1 = 4v_1 \) back into equation (1): \[ 4v_1 = v_1 + v_2 \] This gives: \[ v_2 = 4v_1 - v_1 = 3v_1 \] ### Step 6: Write the Final Ratio The final velocities after the impact are: - \( v_1 \) (velocity of the first sphere) - \( v_2 = 3v_1 \) (velocity of the second sphere) Thus, the ratio of their velocities after the impact is: \[ \frac{v_1}{v_2} = \frac{v_1}{3v_1} = \frac{1}{3} \] ### Final Answer The ratio of their velocities after the impact is \( 1:3 \). ---
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