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A man is walking north with speed 4.5 k...

A man is walking north with speed 4.5 km/h . Another is running west with speed 6 km/h . The velocity (mag. and direction ) of the second relative to the first is

A

7 . 5 km/h at ab angle `tan^(-1)` (3/4) south of west

B

7 . 5 km/h at ab angle `tan^(-1)` (3/4) west of south

C

7 . 5 km/h south west

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To find the velocity of the second man relative to the first, we will follow these steps: ### Step 1: Define the velocities of both men - Let the velocity of the first man (walking north) be represented as: \[ \vec{V_1} = 0 \hat{i} + 4.5 \hat{j} \text{ km/h} \] (where \(\hat{i}\) is the east-west direction and \(\hat{j}\) is the north-south direction). - Let the velocity of the second man (running west) be represented as: \[ \vec{V_2} = -6 \hat{i} + 0 \hat{j} \text{ km/h} \] ### Step 2: Calculate the relative velocity The relative velocity of the second man with respect to the first man is given by: \[ \vec{V_{21}} = \vec{V_2} - \vec{V_1} \] Substituting the values: \[ \vec{V_{21}} = (-6 \hat{i} + 0 \hat{j}) - (0 \hat{i} + 4.5 \hat{j}) = -6 \hat{i} - 4.5 \hat{j} \text{ km/h} \] ### Step 3: Calculate the magnitude of the relative velocity The magnitude of the relative velocity can be calculated using the Pythagorean theorem: \[ |\vec{V_{21}}| = \sqrt{(-6)^2 + (-4.5)^2} \] Calculating the squares: \[ = \sqrt{36 + 20.25} = \sqrt{56.25} = 7.5 \text{ km/h} \] ### Step 4: Calculate the direction of the relative velocity To find the direction, we can use the tangent function: \[ \tan \theta = \frac{\text{opposite}}{\text{adjacent}} = \frac{4.5}{6} \] Calculating \(\theta\): \[ \theta = \tan^{-1}\left(\frac{4.5}{6}\right) \] Calculating the angle: \[ \theta \approx 36.87^\circ \] This angle is measured from the west towards the south, so the direction of the second man's velocity relative to the first man is: \[ \text{South of West} \] ### Final Answer The magnitude of the velocity of the second man relative to the first is \(7.5 \text{ km/h}\) and the direction is \(36.87^\circ\) South of West. ---
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