Home
Class 12
PHYSICS
Three forces P, Q, R are acting at a poi...

Three forces P, Q, R are acting at a point in a plane. The angle between P and Q and Q and R are `150^(@) and 120^(@)` respectively, then for equilibrium, forces P, Q, R are in the ratio

A

`1:2:3`

B

`1:2:3^(1//2)`

C

`3:2:1`

D

`3^(1//2):2:1`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the ratio of the forces P, Q, and R acting at a point in a plane, we can use the law of sines. The angles between the forces are given as follows: - The angle between forces P and Q is \(150^\circ\). - The angle between forces Q and R is \(120^\circ\). ### Step-by-Step Solution: 1. **Identify the Angles**: - Let the angle between forces P and Q be \( \theta_{PQ} = 150^\circ \). - Let the angle between forces Q and R be \( \theta_{QR} = 120^\circ \). - The angle between forces P and R can be calculated as: \[ \theta_{PR} = 360^\circ - \theta_{PQ} - \theta_{QR} = 360^\circ - 150^\circ - 120^\circ = 90^\circ \] 2. **Apply the Law of Sines**: According to the law of sines, for forces in equilibrium: \[ \frac{P}{\sin(\theta_{PR})} = \frac{Q}{\sin(\theta_{RQ})} = \frac{R}{\sin(\theta_{PQ})} \] Substituting the angles: \[ \frac{P}{\sin(90^\circ)} = \frac{Q}{\sin(120^\circ)} = \frac{R}{\sin(150^\circ)} \] 3. **Calculate the Sine Values**: - \( \sin(90^\circ) = 1 \) - \( \sin(120^\circ) = \sin(180^\circ - 60^\circ) = \sin(60^\circ) = \frac{\sqrt{3}}{2} \) - \( \sin(150^\circ) = \sin(180^\circ - 30^\circ) = \sin(30^\circ) = \frac{1}{2} \) 4. **Set Up the Ratios**: Now we can set up the ratios: \[ \frac{P}{1} = \frac{Q}{\frac{\sqrt{3}}{2}} = \frac{R}{\frac{1}{2}} \] 5. **Expressing the Forces in Terms of a Common Variable**: Let \( P = k \), then: \[ Q = k \cdot \frac{\sqrt{3}}{2} \quad \text{and} \quad R = k \cdot \frac{1}{2} \] 6. **Finding the Ratio**: Now we can express the ratio of the forces: \[ P : Q : R = k : k \cdot \frac{\sqrt{3}}{2} : k \cdot \frac{1}{2} \] Dividing through by \( k \): \[ 1 : \frac{\sqrt{3}}{2} : \frac{1}{2} \] To eliminate the fractions, multiply through by 2: \[ 2 : \sqrt{3} : 1 \] 7. **Final Ratio**: Thus, the final ratio of the forces P, Q, and R is: \[ P : Q : R = 2 : \sqrt{3} : 1 \] ### Conclusion: The forces P, Q, and R are in the ratio \( 2 : \sqrt{3} : 1 \).
Promotional Banner

Similar Questions

Explore conceptually related problems

Three forces P,Q and R are acting at a point in the plane. The angle between P & Q and Q & R are 150^(@) & 120^(@) respectively, then for equilibrium, forces P,Q & R are in the ratio

Three forces P, Q and R are acting on a particel in the plane, the angle between P and Q and that between Q and R are 150^(@) and 120^(@) respectively. Then for equilibrium, forces P, Q and R are in the ratio

If P+Q=R and |P|=|Q|= sqrt(3) and |R| ==3 , then the angle between P and Q is

Given that P 12, Q = 5 and R = 13 also P+Q=R, then the angle between P and Q will be

If vec P+ vec Q = vec R and |vec P| = |vec Q| = | vec R| , then angle between vec P and vec Q is