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If z is complex number such that |z|ge2 ...

If z is complex number such that `|z|ge2` then the minimum value of `|z+1/(2)|`

A

is equal to `5/(2)`

B

lies in the interval [1, 2]

C

is strictly greater than `3/(2)`

D

is strictly greater than `3/(2)` but less than `5/(2)`

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AI Generated Solution

The correct Answer is:
To find the minimum value of \( |z + \frac{1}{2}| \) given that \( |z| \geq 2 \), we can follow these steps: ### Step 1: Understand the given condition We know that \( |z| \geq 2 \). This means that the complex number \( z \) lies outside or on the boundary of a circle centered at the origin (0,0) with a radius of 2. ### Step 2: Rewrite the expression We need to minimize \( |z + \frac{1}{2}| \). This can be interpreted as finding the distance from the point \( -\frac{1}{2} \) (which is the point corresponding to \( \frac{1}{2} \) on the real axis) to the points \( z \) that are at least 2 units away from the origin. ### Step 3: Visualize the situation The point \( -\frac{1}{2} \) is located at \( (-0.5, 0) \) on the complex plane. The circle defined by \( |z| = 2 \) has its center at the origin and a radius of 2. ### Step 4: Determine the closest point on the circle to \( -\frac{1}{2} \) To find the minimum distance from \( -\frac{1}{2} \) to the circle \( |z| = 2 \), we need to find the point on the circle that is closest to \( -\frac{1}{2} \). 1. The distance from the origin to \( -\frac{1}{2} \) is \( |-\frac{1}{2}| = \frac{1}{2} \). 2. The distance from the origin to the circle is 2. 3. The closest point on the circle to \( -\frac{1}{2} \) will be along the line connecting the origin to \( -\frac{1}{2} \). ### Step 5: Calculate the distance The distance from \( -\frac{1}{2} \) to the circle can be calculated as follows: - The distance from the origin to \( -\frac{1}{2} \) is \( \frac{1}{2} \). - The radius of the circle is 2. - Therefore, the distance from \( -\frac{1}{2} \) to the circle is \( 2 - \frac{1}{2} = \frac{3}{2} \). ### Step 6: Find the minimum value Thus, the minimum value of \( |z + \frac{1}{2}| \) when \( |z| \geq 2 \) is: \[ \text{Minimum value} = 2 - \frac{1}{2} = \frac{3}{2} \] ### Final Answer The minimum value of \( |z + \frac{1}{2}| \) is \( \frac{3}{2} \).
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