Home
Class 11
MATHS
cos x = b. For what value of b do the ro...

cos x = b. For what value of b do the roots of the equation form an A.P?

A

`-1`

B

`1/2`

C

`sqrt(3)/2`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • SEQUENCE AND SERIES

    OMEGA PUBLICATION|Exercise IMPORTANT QUESTIONS FROM MISCELLANEOUS EXERCISE |22 Videos
  • SAMPLE QUESTIONS PAPER-4 (PUNJAB)

    OMEGA PUBLICATION|Exercise Section- D|7 Videos
  • SETS

    OMEGA PUBLICATION|Exercise Multiple Choice Questions (MCQs)|27 Videos

Similar Questions

Explore conceptually related problems

The least value of p which makes the roots of the equations x^2+5x+p=0 imaginary is:

If a, b, c are real, then both the roots of the equation : (x- b) (x-c) + (x-c) (x-a) + (x-a)(x-b) are always :

If a+b+c=0 and a,b,c are rational. Prove that the roots of the equation (b+c-a)x^(2)+(c+a-b)x+(a+b-c)=0 are rational.

Let a ,b , c ,p ,q be real numbers. Suppose alpha,beta are the roots of the equation x^2+2p x+q=0,alphaa n d1//beta are the roots of the equation a x^2+2b x+c=0,w h e r ebeta^2 !in {-1,0,1}dot Statement 1: (p^2-q)(b^2-a c)geq0 Statement 2: b!=p aorc!=q a

Which one of the following is one of the roots of the equation (b-c) x^2 + (c-a)x+(a-b)=0 ?

The abscissa of the two points A and B are the roots of the equation x^2+2a x-b^2=0 and their ordinates are the roots of the equation x^2+2p x-q^2=0. Find the equation of the circle with AB as diameter. Also, find its radius.

If alpha,beta are the roots of the equation a x^2+b x+c=0, then find the roots of the equation a x^2-b x(x-1)+c(x-1)^2=0 in term of alphaa n dbetadot

Let alpha,beta be the roots of the equation x^2-p x+r=0a n dalpha//2,2beta be the roots of the equation x^2-q x+r=0. Then the value of r is

Let a,b,c,d be distinct real numbers and a and b are the roots of the quadratic equation x^2-2cx-5d=0 . If c and d are the roots of the quadratic equation x^2-2ax-5b=0 then find the numerical value of a+b+c+d .

If a, b, c are real and a!=b , then the roots ofthe equation, 2(a-b)x^2-11(a + b + c) x-3(a-b) = 0 are :