Home
Class 11
MATHS
The equation of the line passing through...

The equation of the line passing through (1,2) and perpendicular to the line `x+y+1=0` is :

A

`y-x+2=0`

B

`y-x+1=0`

C

`y-x-1=0`

D

`y-x-2=0`

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • SAMPLE QUESTION PAPER -2

    OMEGA PUBLICATION|Exercise Section - B (2 MARK) |7 Videos

  • SAMPLE QUESTION PAPER -2

    OMEGA PUBLICATION|Exercise Section - C (4 MARK) |16 Videos

  • SAMPLE QUESTION PAPER -1 (PUNJAB)

    OMEGA PUBLICATION|Exercise SECTION - D|6 Videos

  • SAMPLE QUESTION PAPER -3

    OMEGA PUBLICATION|Exercise Section D (6 MARK) |6 Videos

Similar Questions

Explore conceptually related problems

The equation of the line passing through (1, 1, 1) and perpendicular to the line of intersection of the planes x+2y-4z=0 and 2x-y+2z=0 is

Find the equation of the line passing through the point (-1,3,-2) and perpendicular to the lines : x/1=y/2=z/3 and (x+2)/-3=(y-1)/2=(z+1)/5 .

Find the equation of a line passing through (4,5) and perpendicular to the line 2x + 3y=5.

Find the equation of the line passing through (-3, 5) and perpendicular to the line through the points (2, 5) and (-3, 6).

Find the equations of the line passing through the point (1,-1,2) and perpendicular to the plane 2x-y+3z=5.

Find the vector equation of the line passing through (1, 2, 3) and perpendicular to the plane vecr cdot(hati+2hatj-5hatk) + 9 = 0

Find the vector and cartesian equation of the line passing through the point (2,1,3) and perpendicular to the lines. (x-1)/(1)=(y-2)/(2)=(z-3)/(3) and (x)/(-2)=(y)/(2)=(z)/(5)

Find the vector equations of the line passing through the point (1,-1,2) and perpendicular to the plane 2x-y+3z-5=0.