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Distance between the two planes: 2x+3y+4...

Distance between the two planes: `2x+3y+4z=4` and `4x+6y+8z = 12` is:

A

2 units

B

4 units

C

8 units

D

`(2)/(sqrt(29))` units

Text Solution

Verified by Experts

The correct Answer is:
D
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Distance between the planes 2x + 3y + 4z = 4 and 4x + 6y + 8z = 12 is :

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Knowledge Check

  • Distance between two planes 2x + 3y + 4z = 4 and 4x + 6y + 8z = 16 is :

    A
    2units
    B
    4units
    C
    8units
    D
    `(4)/(sqrt29)` units

  • Distance between two planes : 2x+3y+4z=4 and 4x+6y+8z=12 is

    A
    2 units
    B
    4 units
    C
    8 units
    D
    `(2)/(sqrt(29))` units

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