Check the correctness of relation `F=(mv^(2))/(r )` using dimensional analysis.

Explanation

Step 1 : Dimensional formule of
`[F]=MLT^(-2)`, `[m]=M`, `[v]=LT^(-1)` and `[r]=L`
Step 2 : Now `F=(mv^(2))/(r )impliesMLT^(-2)=(M)(LT^(-1))^(2)(L)^(-1)` or `MLT^(-2)=MLT^(-2)`
Step : Since the dimensions of fundamental units of R.H.S. are equal to that of the L.H.S., so the relation is dimensionally correct.