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For the equation P prop m^(x).v^(y) wher...

For the equation `P prop m^(x).v^(y)` where `P` is momentum, m is mass and v velocity. Then the value of x and y are

A

`x=1, y=2`

B

`x=1, y=1`

C

`x=-1, y=-2`

D

`x=-1, y=-1`

Text Solution

Verified by Experts

The correct Answer is:
B
`p prop m^(x)v^(y)`. Now `p=M^(1)L^(1)T^(-1)`, `v=M^(0)LT^(-1)`
`M^(1)L^(1)T^(-1)=M^(x)L^(y)T^(-1)impliesx=1`, `y=1`
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