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The position of a particle moving on a s...

The position of a particle moving on a straight line path is given by `S = - 3t ^(2) + 2t + 6.` The velocity of body will be zero at time:

A

3s

B

4s

C

`1/3 s`

D

`1/4 s `

Text Solution

Verified by Experts

The correct Answer is:
C
`v = (dS)/( dt) =- 6t + 2 implies v = 0` when
`- 6t + 2 implies v =0 ` when ` - 6t + 2 = 0 implies t = (1)/(3) s.`
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