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The length of a wire is doubled. Then it...

The length of a wire is doubled. Then its Young's modulus

A

remains unchanged

B

becomes double

C

becomes half

D

increases but becomes not exactly double.

Text Solution

Verified by Experts

The correct Answer is:
B
`Y=F/A xx (L)(Delta L)`
when length becomes double then `Delta l=L`.
Therefore `Y=F/A xx (2L)/(L)=(2L)/(A)` = 2 times.
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