A particle carrying a charge `5 mu C` is moving with a velocity `vecv = ( 4 hati + 3 hatk) ms ^(-1)` in a magnetic field `vec B =( 3 hatk + 4 hati) W bm^(-2).` Calculate the force acting on the particle.

Explanation

Force experienced by charged particle in a region of uniform magnetic field `vec B` is given by
`vec F = q ( vec v xx vec B)`
or, `|vecF| = | q ( vec v xx vecB) | or , |vecF| = | q (vec v xx vecB)|`
Now, `|vec v xx vecB = ||{:( hati, hatj , hatk),( 4,3,0),(4,0,3):}|= hati ( 0-0) + hatj ( 1 2 -12) + hatk (0-0) = 0`
`therefore |vec F| = xx 0=0.`