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A proton enters into a magnetic field or...

A proton enters into a magnetic field or intensity `5 xx 10^(-2) T` with velocity `10^(5)`m/s at an angle of `30^(@)` with the field. Calculate the mangitude of force acting on the proton due to this field.

Text Solution

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Here, `B = 5 xx 10 ^(-2) T, v = 10 ^(5) m//s theta = 30^(@), q 1. 6 xx 10 ^(-19) C`
`F = q vB sin theta or F = 1 . 6 cc xx 10^(-19) xx 10 ^(5)xx 5 xx 10 ^(-2) sin 30^(@) = 4 xx 10 ^(-16) N`
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