What is the magnitude of magnetic force per unit length on a wire carrying a current of 8 A and making an angle of `30^(@)` with the direction of magnetic field of `0. 15 T` ?

Explanation

`F = I B l sin theta implies (F)/(l) = I B sin theta = 8 xx 0. 15 xx sin 30 ^(@) = 8 xx 0.15 xx (1)/(2) = 0.6 Nm ^(-1).`