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A galvanometer coll has a resistance of ...

A galvanometer coll has a resistance of 30 ohm and the meter shows full scale deflection for a current of 2 m A. Calculate the value of the resistance required to convert it into an ammeter of range 0 to 1 A. Also calculate the net resistance of the ammeter.

Text Solution

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We are given: `G = 30 Omega, I _(g) = 2 m A = 0. 002 A`
`S = ( I _(R) G )/( I - I _(R)) = ( 0. 002 xx 30)/( 1-0.002)`
`implies S = ( 0.060)/(0.998) = (60)/(998) = 0.06 Omega `
This resistance should be connected in parallel with galvanometer to convert it into an ammeter. Now G and S are in parallel.
`therefore ( I)/( R _(P)) = (1)/(G) + (1)/(S) = R _(P) = ( GS)/( G +S) = ((60)/(998) xx 30)/( (60)/( 998) + 30) = 0.06 Omega.`
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