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A galvanometer of resistance 15 Omega gi...

A galvanometer of resistance `15 Omega` gives full scale difflection for a current of 2 mA. Calculate shunt resistance required to convert it into an ammeter of range `0.5 A.`

Text Solution

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We are given: `G = 15 Omega , I _(g) = m A = 2 xx 10 ^(-3) A`
We know that, Resistance required , ` S = ( I _(R))/( I - I _(R)) G.`
`therefore S = ( 2 xx 10 ^(- 3))/( 5 - (2 xx 10 ^(-3)))xx 15 = 6 xx 10 ^(-3) Omega.`
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