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A galvanometer has a resistance of 100 o...

A galvanometer has a resistance of 100 ohm. A resistance of `1 Omega` is connected across its terminals. WHich part of the total current flows through the galvanometer? Draw the diagram.

Text Solution

Verified by Experts

We are given: ` G = 100 Omega `
`S = 1 Omega`
We know that `I _(g) G = (I - I _(g)) S`
`implies I _(g) ( G + S) = IS`
`implies (I _(g))/( I ) = (S)/( G + S)`
`implies (I _(g))/( I ) = (I)/(100 + 1) = (I)/(101) `
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