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In a plane electromagnetic wave, the ele...

In a plane electromagnetic wave, the electric field oscillates with a frequency of `2 xx 10^(10) s^(-1)` and an amplitude of `40V m^(-1)`.
What is the wavelength of the wave?

Text Solution

Verified by Experts

We are given, `v= 2 xx 10^(10) s^(-1), E= 40 V m^(-1)`
We know that, `c= v lamda`
`lamda = (c )/(v)= (3 xx 10^(8))/(2 xx 10^(10)) = 1.5 xx 10^(-2)m`
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