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In a plane e.m. wave the electric field ...

In a plane e.m. wave the electric field oscillates sinusoidally at a frequency of `2 xx10^10` Hz and amplitude `48 Vm^-1` . What is the magnitude of oscillating magnetic field?

Text Solution

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We are given: `v= 2 xx 10^(10)Hz`
`c= 3 xx 10^(8) ms^(-1), E= 48 V//m`
We are to calculate, Wavelength `(lamda)`, Magnetic field (B)
Using relation: `c= v lamda`, we have `lamda= (c )/(v) or lamda = (3 xx 10^(8))/(2 xx 10^(10))= 1.5 xx 10^(-2)m`
Also, `c= (E )/(B) rArr B= (E )/(c)= (48)/(3 xx 10^(8))= 1.6 xx 10^(-7) Wb//m^(2)`
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